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单选题Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()Aprocess(bytes);BBitUtils.process(bytes);Capp.BitUtils.process(bytes);Dutil.BitUtils.process(bytes);Eimport util.BitUtils

题目
单选题
Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()
A

process(bytes);

B

BitUtils.process(bytes);

C

app.BitUtils.process(bytes);

D

util.BitUtils.process(bytes);

E

import util.BitUtils.*; process(bytes);

F

SomeApp cannot use the process method in BitUtils.


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更多“单选题Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()A process(bytes);B BitUtils.process(bytes);C app.BitUtils.process(bytes);D util.BitUtils.process(bytes);E import uti”相关问题
  • 第1题:

    UPSR protection switching is initiated by (), while BLSR is initiated by ().

    A. the K1 SONET byte; the K2 SONET byte

    B. the K2 SONET byte;the K1 SONET byte

    C. transmitter switching;receiver detection

    D. Line Overhead bytes;Path Overhead bytes

    E. Path Overhead bytes;Line Overhead bytes


    参考答案:E

  • 第2题:

    WhichofthefollowingistrueabouttheMPLSheaderanditsEXPfieldsize?()

    A.TheMPLSheaderis2bytes,andtheEXPfieldis3bitslong.

    B.TheMPLSheaderis1byte,andtheEXPfieldis3bitslong.

    C.TheMPLSheaderis4bytes,andtheEXPfieldis3bitslong.

    D.TheMPLSheaderis3bytes,andtheEXPfieldis3bitslong.


    参考答案:C

  • 第3题:

    Which two statements are true when the extended system ID feature is enabled? ()

    • A、The BID is made up of the bridge priority value(two bytes) and bridge MAC address (six bytes).
    • B、The BID is made up of the bridge priority (four bits), the system ID (12 bits), and a bridge MAC address (48 bits).
    • C、The BID is made up of the system ID (six bytes) and bridge priority value (two bytes).
    • D、The system ID value is the VLAN ID (VID).
    • E、The system ID value is a unique MAC address allocated from a pool of MAC addresses assigned to the switch or module.
    • F、The system ID value is a hex number used to measure the preference of a bridge in the spanning-tree algorithm.

    正确答案:B,D

  • 第4题:

    UPSR protection switching is initiated by (), while BLSR is initiated by ().

    • A、the K1 SONET byte; the K2 SONET byte
    • B、the K2 SONET byte;the K1 SONET byte
    • C、transmitter switching;receiver detection
    • D、Line Overhead bytes;Path Overhead bytes
    • E、Path Overhead bytes;Line Overhead bytes

    正确答案:E

  • 第5题:

    Given classes defined in two different files: 1.package util; 2.public class BitUtils{ 3.private static void process(byte[]b){} 4.} 1.package app; 2.public class SomeApp{ 3.public static void main(String[]args){ 4.byte[]bytes=newbyte[256]; 5.//insert code here 6.} 7.} What is required at line 5 in class SomeApp to use the process method of BitUtils?()

    • A、process(bytes);
    • B、BitUtils.process(bytes);
    • C、app.BitUtils.process(bytes);
    • D、util.BitUtils.process(bytes);
    • E、importutil.BitUtils.*;process(bytes);
    • F、SomeApp cannot use the process method in BitUtils.

    正确答案:F

  • 第6题:

    What are the header sizes for point-to-point and multi-point GRE(also known asmGRE) with tunnel key?()

    • A、 4 bytes for both
    • B、 4 bytes, and 8 bytes respectively
    • C、 8 bytes for both
    • D、 24 bytes for both

    正确答案:B

  • 第7题:

    Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. public static void process(byte[]) { /* more code here */ }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?() 

    • A、 process(bytes);
    • B、 BitUtils.process(bytes);
    • C、 util.BitUtils.process(bytes);
    • D、 SomeApp cannot use methods in BitUtils.
    • E、 import util.BitUtils.*; process(bytes);

    正确答案:C

  • 第8题:

    单选题
    Given classes defined in two different files:What is required at line 5 in class SomeApp to use the process method of BitUtils?()
    A

    process(bytes);

    B

    BitUtils.process(bytes);

    C

    util.BitUtils.process(bytes);

    D

    SomeApp cannot use methods in BitUtils.

    E

    import util.BitUtils.*; process(bytes);


    正确答案: A
    解析: 暂无解析

  • 第9题:

    单选题
    A router receives an IPv6 packet which is 2000 bytes in length. The MTU of the outgoing interface is 1500 bytes. What action will the router take?()
    A

    forwards the packet

    B

    fragments the packet

    C

    drops the packet silently

    D

    drops the packet and sends an ICMP message


    正确答案: A
    解析: 暂无解析

  • 第10题:

    单选题
    Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. private static void process(byte[] b) { }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?()
    A

     process(bytes);

    B

     BitUtils.process(bytes);

    C

     app.BitUtils.process(bytes);

    D

     util.BitUtils.process(bytes);

    E

     import util.BitUtils. *; process(bytes);

    F

     SomeApp cannot use the process method in BitUtils.


    正确答案: A
    解析: 暂无解析

  • 第11题:

    单选题
    Given classes defined in two different files: 1.package util; 2.public class BitUtils{ 3.private static void process(byte[]b){} 4.} 1.package app; 2.public class SomeApp{ 3.public static void main(String[]args){ 4.byte[]bytes=newbyte[256]; 5.//insert code here 6.} 7.} What is required at line 5 in class SomeApp to use the process method of BitUtils?()
    A

    process(bytes);

    B

    BitUtils.process(bytes);

    C

    app.BitUtils.process(bytes);

    D

    util.BitUtils.process(bytes);

    E

    importutil.BitUtils.*;process(bytes);

    F

    SomeApp cannot use the process method in BitUtils.


    正确答案: E
    解析: 暂无解析

  • 第12题:

    多选题
    Which two statements are true when the extended system ID feature is enabled? ()
    A

    The BID is made up of the bridge priority value(two bytes) and bridge MAC address (six bytes).

    B

    The BID is made up of the bridge priority (four bits), the system ID (12 bits), and a bridge MAC address (48 bits).

    C

    The BID is made up of the system ID (six bytes) and bridge priority value (two bytes).

    D

    The system ID value is the VLAN ID (VID).

    E

    The system ID value is a unique MAC address allocated from a pool of MAC addresses assigned to the switch or module.

    F

    The system ID value is a hex number used to measure the preference of a bridge in the spanning-tree algorithm.


    正确答案: B,F
    解析: 暂无解析

  • 第13题:

    Usersofasite-to-siteVPNarereportingperformanceproblems.TheVPNconnectionemploysIPSecandGREandtraversesseveralEthernetsegments.TheVPNpacketsarebeing fragmentedastheytraversethelinks.Whatwouldbetwomethodstoovercomethisproblem?()

    A.EmploypathMTUdiscovery.

    B.SettheMTUhigherthan1500bytes.

    C.Turnoffpre-fragmentationforIPSec.

    D.SettheMTUvalueto1400bytes.


    参考答案:A, D

  • 第14题:

    Refer to the exhibit. What is the meaning of the output MTU 1500 bytes?()

    A.Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.

    B.Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.

    C.Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.

    D.Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.

    E.Themaximumframesizethatcantraversethisinterfaceis1500bytes.


    参考答案:D

  • 第15题:

    What are disadvantages of Network Address Translation Transparency?()

    • A、There is no disadvantage.
    • B、It will add 16 bytes per packet of overhead(8 bytes UDP header, and 8 bytes of NON-IKE Marker).
    • C、It will add 36 bytes per packet of overhead (20 bytes of IP header, 8 bytes of UDP header, 8 bytes of NON-IKE Marker).
    • D、It will require that both crypto peers support this feature in the IOS version. Both crypto peers must also have this feature enabled.

    正确答案:B,D

  • 第16题:

    A router receives an IPv6 packet which is 2000 bytes in length. The MTU of the outgoing interface is 1500 bytes. What action will the router take?()

    • A、forwards the packet
    • B、fragments the packet
    • C、drops the packet silently
    • D、drops the packet and sends an ICMP message

    正确答案:D

  • 第17题:

    IS-IS的NET地址至少需要()bytes,其中,()bytes的(),()bytes的()和()bytes的(),最多为()bytes.


    正确答案:8;1;区域地址空间;6;systemid;1;nsel;20

  • 第18题:

    Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. private static void process(byte[] b) { }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?() 

    • A、 process(bytes);
    • B、 BitUtils.process(bytes);
    • C、 app.BitUtils.process(bytes);
    • D、 util.BitUtils.process(bytes);
    • E、 import util.BitUtils. *; process(bytes);
    • F、 SomeApp cannot use the process method in BitUtils.

    正确答案:F

  • 第19题:

    单选题
    Refer to the exhibit. What is the meaning of the output MTU 1500 bytes?()
    A

    Themaximumnumberofbytesthatcantraversethisinterfacepersecondis1500.

    B

    Theminimumsegmentsizethatcantraversethisinterfaceis1500bytes.

    C

    Theminimumpacketsizethatcantraversethisinterfaceis1500bytes.

    D

    Themaximumpacketsizethatcantraversethisinterfaceis1500bytes.

    E

    Themaximumframesizethatcantraversethisinterfaceis1500bytes.


    正确答案: B
    解析: 暂无解析

  • 第20题:

    单选题
    UPSR protection switching is initiated by (), while BLSR is initiated by ().
    A

    the K1 SONET byte; the K2 SONET byte

    B

    the K2 SONET byte;the K1 SONET byte

    C

    transmitter switching;receiver detection

    D

    Line Overhead bytes;Path Overhead bytes

    E

    Path Overhead bytes;Line Overhead bytes


    正确答案: D
    解析: 暂无解析

  • 第21题:

    单选题
    Given classes defined in two different files: What is required at line 5 in class SomeApp to use the process method of BitUtils?()
    A

    process(bytes);

    B

    BitUtils.process(bytes);

    C

    app.BitUtils.process(bytes);

    D

    util.BitUtils.process(bytes);

    E

    import util.BitUtils.*; process(bytes);

    F

    SomeApp cannot use the process method in BitUtils.


    正确答案: E
    解析: 暂无解析

  • 第22题:

    单选题
    Given classes defined in two different files:  1. package util;  2. public class BitUtils {  3. public static void process(byte[]) { /* more code here */ }  4. }  1. package app;  2. public class SomeApp {  3. public static void main(String[] args) {  4. byte[] bytes = new byte[256];  5. // insert code here  6. }  7. }  What is required at line 5 in class SomeApp to use the process method of BitUtils?()
    A

     process(bytes);

    B

     BitUtils.process(bytes);

    C

     util.BitUtils.process(bytes);

    D

     SomeApp cannot use methods in BitUtils.

    E

     import util.BitUtils.*; process(bytes);


    正确答案: E
    解析: 暂无解析

  • 第23题:

    单选题
    What are the header sizes for point-to-point and multi-point GRE(also known asmGRE) with tunnel key?()
    A

     4 bytes for both

    B

     4 bytes, and 8 bytes respectively

    C

     8 bytes for both

    D

     24 bytes for both


    正确答案: D
    解析: 暂无解析

  • 第24题:

    多选题
    What are disadvantages of Network Address Translation Transparency?()
    A

    There is no disadvantage.

    B

    It will add 16 bytes per packet of overhead(8 bytes UDP header, and 8 bytes of NON-IKE Marker).

    C

    It will add 36 bytes per packet of overhead (20 bytes of IP header, 8 bytes of UDP header, 8 bytes of NON-IKE Marker).

    D

    It will require that both crypto peers support this feature in the IOS version. Both crypto peers must also have this feature enabled.


    正确答案: D,B
    解析: 暂无解析