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“() your best? It’s not satisfactory. I’m afraid you will have to do it again.”A.Do you tryB.Have you triedC.Are you tryingD.Have you been trying

题目
“() your best? It’s not satisfactory. I’m afraid you will have to do it again.”

A.Do you try

B.Have you tried

C.Are you trying

D.Have you been trying

相似考题

1.You look(). What () you () ?A、tire, did…doB、tiring, have…doneC、tired, do…doD、tired, have…been doing

2.—Where____you____lunch?—Athome．TherewasnoschoollunchA．did；haveB．are；havingC．will；haveD．do；have

3.What's ( )job? Are ( ) British?A. your, yourB. you, yourC. your, you

4.9． _______you _______ stay at home today?A． Do ; have toB． Must; have toC． Have; toD． Do ; must

参考答案和解析
参考答案：B
更多““() your best? It’s not satisfactory. I’m afraid you will have to do it again.” ”相关问题

  • 第1题：

    （ ） – Is Miss White __________ English teacher, Maria?

    – No, she teaches __________ geography.

    A．your；my

    B．you；mine

    C．you；us

    D．your；us


    正确答案：D

  • 第2题：

    以下能正确计算1×2×3×4...×10的程序段是

    A．i=1; s=1; do { s=s*i; i++; } while(i＜=10);

    B．do { i=1; s=1; s=s*i; i++; } while(i＜=10);

    C．do { i=1; s=0; s=s*i; i++; } while(i＜=10);

    D．i=1; s=0; do { s=s*i; i++; } while(i＜=10);


    i=1;s=1; do{ s=s*i; i++; }while(i＜=10)

  • 第3题：

    以下能正确计算10！的程序段是 。

    A．do {i=1;s=1;; s=s*i; i++; }while(i＜=10);

    B．do{i=1;s=0 s=s*i; i++; while(i＜=10);

    C．i=1;s=1; do{s=s*i; i++; }while(i＜=10);

    D．i=1;s=0; do{s=s*i; i++; }while(i＜=10);


    死循环

  • 第4题：

    You look（） What（）you（）?

    Atire；did；do

    Btiring；have；done

    Ctired；do；do

    Dtired；have；been doing


    D
    略

  • 第5题：

    以下能正确计算1+2+3+…+10的程序段是 。

    A．i=1; s=1; do {s=s+i; i++;} while (i＜10);

    B．do {i=1;s=0; s=s+i; i++;} while (i＜=10);

    C．do {i=1;s=1; s=s+i; i++;} while (i＜=10);

    D．i=1,s=0; do {s=s+i; i++;} while (i＜=10);

    E．i=1; s=1; do {s=s+i; i++;} while (i＜=10);

    F．i=1,s=0; do {s=s+i; i++;} while (i＜10);


    C

  • 第6题：

    以下能正确计算1×2×3×…×10的程序段是 。

    A．do {i=1;s=1; s=s*i; i++; } while(i＜=10);

    B．do {i=1;s=0; s=s*i; i++; } while(i＜=10);

    C．i=1;s=1; do {s=s*i; i++; } while(i＜=10);

    D．i=1;s=0; do {s=s*i; i++; } while(i＜=10);


    B

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