What was probably the direct result of Olivetti,s falling behind in electronic technology?
A.A dtiano’s death.
B.A period of financial problem
C.its faster progress
D.Its agreements with other companies
第1题:
A.AddthefollowingOnPreRendereventhandlertotheasp:DropDownList
B.AddthefollowingOnPreRendereventhandlertotheasp:DropDownList
C.Addthefollowingeventhandlertothepagecode-behind.
D.Addthefollowingeventhandlertothepagecode-behind.
第2题:
9、阅读以下程序,填写运行结果________________. def f(n): s=str(n) result='' for i in range(0,len(s)): result=s[i]+result return result print(f(345))
第3题:
4.下面代码片断的输出结果是什么? byte b = 10; char c = 'b'; short s = 100; int i = 4, result1 = b * c; int result2 = ++i - b-- + s++; System.out.println("c=" + (byte) c); System.out.println("result1=" + result1); System.out.println("result2=" + result2);
第4题:
A.Direct-pathexportistypicallyfaster.
B.Direct-pathexportcanbeinvokedinteractively.
C.Direct-pathexportischaractersetindependent.
D.Direct-pathexportbypassestheSQL-commandprocessinglayer.
E.Direct-pathexportcanbeusedtoexportrowscontainingLOBsandBFILEs.
第5题:
假设$s0中存放着数组A的起始地址 数组A的定义为:int A[400]; 以下这段MIPS代码的功能是什么? addi $t1, $s0, 1600 addi $s2 $zero, 0 addi LOOP: lw $s1, 0($s0) add $s2, $s2, $s1 lw $s1, 4($s0) add $s2, $s2, $s1 addi $s0, $s0, 8 bne $t1, $s0, LOOP
A.int result=0; for (i=400; i>0; i--) { result += A[i]; }
B.int result=0; for (i=0; i<400; i+=2 ) { result += A[i]; result += A[i+1]; }
C.int result=0; for (i=400; i>0; i-=2) { result += A[i]; result += A[i+1]; }
D.int result=0; for (i=0; i<1600; i+=8 ) { result += A[i]; result += A[i+4]; }
第6题:
在电子商务的英文表述中,最常用的词组是()
A.Electronic-Commerce
B.Electronic-Business
C.Internet-Commerce(I-C)
D.Internet-Business(I-B)