Could you find someone _________?
(A) for me to play tennis with
(B) play tennis with
(C) for me to play tennis
(D) playing tennis with
第1题:
49.—What about some drinks?
—__________.
A. Help, yourself
B. Good idea
C. You're welcome
D. Me,too
第2题:
Me,you是两个初始集合,则下列关于派生集合定义方式正确的是
A.link/me,you/:a;
B.link(me,you):a;
C.link/me you/a;
D.link(me,you)/a;
第3题:
9、以下对于字符串的相关操作,正确的输出结果是哪些选项?
A.>>> 'Life is short, you need Python.'.find('you') 15
B.>>> seq = [1, 2, 3, 4]; >>> sep = '+'; >>> sep.join(seq) '1+2+3+4'
C.>>> print('{:5.3f}'.format(math.pi)) 3.1416
D.>>> print('you' in 'Life is short, you need Python.') True
第4题:
第5题:
以下对于字符串的相关操作,正确的输出结果是哪些选项?
A.>>> 'Life is short, you need Python.'.find('you') 15
B.>>> seq = [1, 2, 3, 4]; >>> sep = '+'; >>> sep.join(seq) '1+2+3+4'
C.>>> print('{:5.3f}'.format(math.pi)) 3.1416
D.>>> print('you' in 'Life is short, you need Python.') True
第6题:
me是一个包含3个成员属性为a的集合,you是一个包含2个成员属性为b的集合,则要定义一个2行3列的矩阵所对应的派生集合方法中正确的是
A.ps(me,you):c;
B.ps(you,me):c;
C.ps(a,b):c;
D.ps(b,a):c;