itgle.com
Yes,_____is difficult to find a job nowadays, but_____is more difficult is try to find such a job with a high salary but few things to do.A、it, it.B、what, what.C、it, what.D、what, it. C
题目
A、it, it.
B、what, what.
C、it, what.
D、what, it. C
相似考题
参考答案和解析
更多“Yes,_____is difficult to find a job nowadays, but_____is more difficult is try to find such a job with a high salary but few things to do. ”相关问题
-
第1题：
When setting arguments for a job, which procedure do you use for types that cannot be implicitly converted to and from a VARCHAR2 datatype?()A. SET_JOB_ARGUMENT_VALUE
B. SET_JOB_VALUE_ANYDATA
C. SET_JOB_ANYDATA_VALUE
D. SET_SPECIAL_JOB_VALUE
E. SET_JOB_ANYTYPE_VALUE
参考答案：C
-
第2题：
Click the Exhibit button to examine the structures of the EMPLOYEES, DEPARTMENTS, and TAX tables.For which situation would you use a nonequijoin query?()
A.to find the tax percentage for each of the employees
B.to list the name, job_id, and manager name for all the employees
C.to find the name, salary, and the department name of employees who are not working with Smith
D.to find the number of employees working for the Administrative department and earning less than 4000
E.to display name, salary, manager ID, and department name of all the employees, even if the employees do not have a department ID assigned
参考答案：A
-
第3题：
12、利用命令find查找当前目录下的以“.c”结尾的文件，并逐页显示的命令是（）。
A．find . -name “？.c” | more
B．find . -name “#.c” | more
C．find . -name “!*.c” | more
D．find . -name “*.c” | more
正确 -
第4题：
Examine the data in the EMPLOYEES and EMP_HIST tables:EMPLOYEESNAME DEPT_ID MGR_ID JOB_ID SALARYEMPLOYEE_ID101 Smith 20 120 SA_REP 4000102 Martin 10 105 CLERK 2500103 Chris 20 120 IT_ADMIN 4200104 John 30 108 HR_CLERK 2500105 Diana 30 108 IT_ADMIN 5000106 Smith 40 110 AD_ASST 3000108 Jennifer 30 110 HR_DIR 6500110 Bob 40 EX_DIR 8000120 Ravi 20 110 SA_DIR 6500EMP HISTEMPLOYEE_ID NAME JOB_ID SALARY101 Smith SA_CLERK 2000103 Chris IT_CLERK 2200104 John HR_CLERK 2000106 Smith AD_ASST 3000108 Jennifer HR_MGR 4500The EMP_HIST table is updated at the end of every year. The employee ID, name, job ID, and salary of each existing employee are modified with the latest data. New employee details are added to the table.Which statement accomplishes this task?（）
A. UPDATE emp_hist SET employee_id, name, job_id, salary = (SELECT employee_id, name, job_id, salary FROM employees) WHERE employee_id IN (SELECT employee_id FROM employees);
B. MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT VALUES (e.employee id, e.name, job id, e.salary);
C. MERGE INTO emp_hist eh USING employees e ON (eh.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE emp hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employees_id, e.name, e.job_id, e.salary);
D. MERGE INTO emp_hist eh USING employees e WHEN MATCHED THEN UPDATE emp_hist SET eh.name = e.name, eh.job_id = e.job_id, eh.salary = e.salary WHEN NOT MATCHED THEN INSERT INTO emp_hist VALUES (e.employees_id, e.name, e.job_id, e.salary);
参考答案：B
-
第5题：
设有一组作业，它们的作业提交时刻及估计运行时间如下所示： 作业号 提交时刻 估计运行时间(分钟) Job1 8：30 70 Job2 9：10 30 Job3 9：30 15 Job4 9：50 5 在单道批处理方式下，采用短作业优先调度算法，作业的执行顺序为
A．Job1，Job4，Job3，Job2
B．Job1，Job3，Job4，Job2
C．Job4，Job3，Job2，Job1
D．Job4，Job1，Job2，Job3
正确答案：B
解析：本题考查短作业优先调度算法的概念。短作业(进程)优先调度算法是指对短作业或短进程优先调度的算法。它们可以分别用于作业调度和进程调度。短作业优先调度算法，是从后备队列中选择一个或若干个估计运行时间最短的作业，将它们调入内存运行。而短进程优先调度算法，则是从就绪队列中选出一估计运行时间最短的进程，将处理机分配给它，使它立即执行并一直执行到完成，或发生某事件而被阻塞放弃处理机时，再重新调度。进程首先执行的是Job1，该作业到9:40完成，此时Job2和Job3在等待队列中，按照短作业调度算法，此时执行Job3。Job3在10:10，此时等待队列中有Job2和Job4作业，此时执行Job4，最后执行Job2。正确答案为选项B。 -
第6题：
利用命令find查找当前目录下的以“.c”结尾的文件，并逐页显示的命令是（）。
A．find . -name “？.c” | more
B．find . -name “#.c” | more
C．find . -name “!*.c” | more
D．find . -name “*.c” | more
D