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By his genius he()all these old stories()masterpieces of his life.A、put; intoB、turned; intoC、wrote; asD、set; as

题目
By his genius he()all these old stories()masterpieces of his life.

A、put; into

B、turned; into

C、wrote; as

D、set; as

相似考题

1.7． Hi! This is_______ new teacher．__________ name is Linda．A． your; MyB． his; YourC． your ; HerD． her; His

2.在HIS上出现”OFFSCALE”信息,表示:().A、地图超出HIS的显示范围B、TCAS超出HIS的显示范围C、气象雷达超出HIS的显示范围

3.I must have thrown away ( ) by mistake.A、his’B、hisC、he’sD、he

4.His______(refuse) to come to our wedding upset the new couple.

更多“By his genius he()all these old stories()masterpieces of his life. ”相关问题

  • 第1题：

    下列不属于盒子化产品的是()

    A.HCS1600

    B.HCS2600

    C.HIS1600

    D.HIS2600


    参考答案：D

  • 第2题：

    You are signing on a deck officer，who will be designated as one of the GMDSS operators，before sailing foreign．Which statement is TRUE ________．

    A.He/she must have an STCW certificate endorsed as“Valid for Service on Vessels Operating in the GMDSS System”

    B.He/she must present either an FCC-issued license or a Coast Guard-issued license

    C.You must consult the“List of Qualifications”on the reverse of his/her FCC-issued license

    D.His/her Merchant Mariners Document must have an added endorsement as “Radio Electronics Officer”


    正确答案：A

  • 第3题：

    4个基因（MAT, HIS4, THR4, and LEU2)在啤酒酵母染色体III 上相互距离如下 HIS4 ↔ MAT 37 cM，THR4 ↔ LEU2 35 cM，LEU2 ↔ HIS4 23 cM， MAT ↔ LEU2 16 cM， MAT ↔ THR4 20 cM。 基因的顺序 为 HIS4 -MAT - THR4 - LEU2。


    错误

  • 第4题：

    12．

    A． My

    B． He

    C． His


    正确答案：C
    12．C【解析】承接上一句。他有一个弟弟”，“他的名子叫汤姆”。

  • 第5题：

    The working parent is not willing to listen to her (his) four-year-old child talking about hissandbox games because she (he) is___________.

    A.boring
    B.very tired
    C.busy
    D.angry

    答案：B
    解析：
    通读第四段，注意短语“fartoo beaten down”，可知父母每天工作非常辛苦和疲惫。所以和孩子的交流沟通少了。正确答案为B。A、C、D都不符合题意。

  • 第6题：

    【单选题】下面程序的输出是。 main（) {enum team {my,your=4,his,her=his+10}; printf（"%d%d%d%dn",my,your,his,her);}

    A．0 1 2 3

    B．0 4 0 10

    C．0 4 5 15

    D．l 4 5 15


    DDBBCC C语言对枚举的定义规定：在枚举中声明的各个枚举元素，如果没有明确指出某个枚举元素的值，它的上一个元素存在并有明确值的情况下，这个枚举元素的值为其上一个元素的值+1。在本题中，没有明确说明枚举元素em3的值，则em3=em2+1=1+1=2，进而可知，在printf()打印函数中，要打印的数组元素是aa[3]、aa[1]、aa[2]，因此最后的打印结果应当为“DDBBCC”。

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