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I cannot () this signature.A、identificationB、identityC、identicalD、identify

题目
I cannot () this signature.

A、identification

B、identity

C、identical

D、identify

相似考题

1.现有以下语句: i=1; for (;i＜=100;i++) sum+=i;A．for(i-1;;i++) { sum+--i; if(i==100) break; }B．for(i=1;i＜=100;) { sum+=i; i++; }C．i=1; for(;i＜=100;) { sum+=-i; }D．i=1; for(;;) { sum+=i; if(i==100) break; i++; }

2.与“for(i=0；i＜10；i++)putchar('a'+i)；”功能不同的语句是______。A．for(i=0；i＜10；)putchar('a'+(++i))；B．for(i=0；i＜10；)putchar('a'+(i++))；C．for(i=0；i＜10；putchar('a'+i)，i++)；D．for(i=0；i＜=9；i++)putchar('a'+i)；

3.Without the instrument，we__________A．cannot’hardly do nothingB．cannot hardly do anythingC．can hardly do nothingD．can hardly do anything

4.The teacher ______ be in the office; maybe he is in the library.A、mightB、couldC、may notD、can not

更多“I cannot () this signature. ”相关问题

  • 第1题：

    小学英语?阅读
    一、考题回顾



    二、考题解析
    【教案】
    Teaching aims:
    Knowledge aim:
    Students can master the sentence :”what time is it? it is ..” and you can/ can not ...”
    Ability aim:
    Students can improve their reading skills including scanning and skimming skills
    Emotional aim:
    Students can be more interested in English and take part in activities.
    Key and difficult point:
    Key Point: know how to ask about the time and master the sentences::”what time is it? it is ..” and you can/ can not ...”
    Difficult Point: use the sentence structure in daily life.
    Teaching procedure:
    Step 1: Warming-up
    1. Greetings.
    2. Ask students how did they spend their weekend.
    3. Ask students “do you know wangfujing street in Beijing”
    Step 2: Pre-reading
    1. show a picture about wangfujing street and ask “what can you see in this picture”
    2. draw a clock and ask students “Do you know how to ask about time?” and “what can you do at this time?
    Step 3: While-reading
    Global reading: Ask students :”how many characters in the dialogue?” and “where are they”
    Detailed reading: what does Jenny buy and who will get the gift?



    Step4: Post-reading
    1. Role-play: two students in a group. One student act as traveller and one student is tour guide. Give them 5 minutes to make dialogue with what we have learnt today.
    Step5: Summary and Homework
    Summary: ask a student to conclude the content of the lesson and summarize with the whole class.
    Homework: ask students to practice the sentence structure learned today with desk mates after class.
    Blackboard design:



    1. What will you do if the students don't finish your homework?
    2. What reading skills are used in the passage?


    答案：
    解析：
    1.
    Homework is an important means to show students' intelligence and improve their quality. Doing homework is the summary and consolidation of the knowledge learned, so doing homework is one of the important means for students to master knowledge.Third, fourth grade students such as not to assign homework is not conducive to the timely review of students to consolidate the knowledge, is not conducive to students to develop good learning habits. Therefore, how to help students homework on time with high quality is the primary task of every teacher.
    firstly, I will talk to students to analyze the reason why he did not finish the homework. The reason maybe as follows: He dose not how to do it without any help. or he thinks homework is so much and can not finish it and so on. Then I will take action according to the reasons.
    2.
    In order to make students be more interested in reading and can understand the knowledge clearly, I use detailed reading to make students find the detail information and global reading to find the how many characters in the dialogue. In the reading passage. students can master and scanning skills and skimming skills. They can understand the passage step by step.

  • 第2题：

    int a[10]; 给数组a的所有元素分别赋值为1、2、3、……的语句是（）。

    A．for(i=1;i＜11;i++)a[i+1]=i;

    B．for(i=1;i＜11;i++)a[i-1]=i;

    C．for(i=1;i＜11;i++)a[i]=i;

    D．for(i=1;i＜11;i++)a[0]=1;


    for(i=1;i＜11;i++)a[i-1]=i;

  • 第3题：

    以下哪个for语句是正确的？

    A．for(i=0; i＜10; i++);

    B．for(i=0; i＜10, i++);

    C．for(i=0, i＜10; i++);

    D．for(i=0, i＜10, i++);

    E．for(i=0; i＜10);

    F．for(i=0; i++);


    for a in range(1,3):

  • 第4题：

    ()are?those?costs?that?cannot?be?directly?traced?to?a specific?project?and?therefore?will?be?accumulated?and allocated?equitably?over?multiple?projects?by?some?approved and?documented?accounting?procedure.

    A.Direct costs
    B.Operation costs
    C.Indirect costs
    D.Implement costs

    答案：C
    解析：
    本题翻译：
    （）是指不能直接追溯到特定项目的成本，因此将通过一些批准和记录的会计程序在多个项目上平均累计和分配。
    A.直接成本B.运营成本C.间接成本D.实施成本
    本题考查成本的分类，不能直接的就可以理解为间接，间接成本：来自一般管理费用科目或几个项目共同负担的项目成本所分摊给本项目的费用。
    而成本管理中不是涉及运营成本、实施成本。排除BD选项。所以此题选择C选项。

  • 第5题：

    int a[10]; 给数组a的所有元素分别赋值为1、2、3、……的语句是（）。

    A．for(i=1;i＜11;i++)a[i]=i;

    B．for(i=1;i＜11;i++)a[i-1]=i;

    C．for(i=1;i＜11;i++)a[i+1]=i;

    D．for(i=1;i＜11;i++)a[0]=1;


    错误

  • 第6题：

    int a[5]={1,0,3,4,-2}; 以下正确的打擂台算法求最小值的是

    A．int min,i; for(i=0;i＜5;i++) if(a[i]＜min) min=a[i];

    B．int min=a[0],i; for(i=0;i＜5;i++) if(a[i]＜min) min=a[i];

    C．int min=a[1],i; for(i=0;i＜5;i++) if(a[i]＞min) min=a[i];

    D．int min=a[0],i; for(i=1;i＜5;i++) if(a[i]＜min) min=a[i];


    D

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