The light of his room is still on, so he ( ) out.A、mustn't have goneB、mustn't goC、can't have goneD、can't go

The working parent is not willing to listen to her (his) four-year-old child talking about hissandbox games because she (he) is___________.

A.boring
B.very tired
C.busy
D.angry

阅读下列说明和C++代码，回答问题，将解答填入答题纸的对应栏内。
【说明】
某灯具厂商欲生产一个灯具遥控器，该遥控器具有7个可编程的插槽，每个插槽都有开关按钮，对应着一个不同的灯。利用该遥控器能够统一控制房间中该厂商所有品牌灯具的开关，现采用Command(命令)模式实现该遥控器的软件部分。Command模式的类图如下图所示。

【C++代码】

class Light {public: Light(stringname) { /* 代码省略 */ } void on() {/* 代码省略 */ } // 开灯 void off() {/* 代码省略 */ } // 关灯};class Command {public: （1） ;}；class LightOnCommand:public Command { // 开灯命令private: Light* light;public: LightOnCommand(Light* light) { this->light=light; } voidexecute() { （2） ; }};class LightOffCommand:public Command { // 关灯命令private: Light *light;public: LightOffCommand(Light* light) { this->light=light; } voidexecute() { （3） ; }};class RemoteControl{ // 遥控器private: Command*onCommands[7]; Command*offCommands[7];public: RemoteControl() { /* 代码省略*/ } voidsetCommand(int slot, Command* onCommand, Command* offCommand) { （4） =onCommand; （5） =offCommand; } voidonButtonWasPushed(int slot) { （6） ; } voidoffButtonWasPushed(int slot) { （7） ; }};int main() { RemoteControl* remoteControl=new RemoteControl(); Light*livingRoomLight=new Light("Living Room"); Light*kitchenLight=new Light("kitchen"); LightOnCommand*livingRoomLightOn=newLightOnCommand(livingRoomLight); LightOffCommand* livingRoomLightOff=newLightOffCommand(livingRoomLight); LightOnCommand*kitchenLightOn=new LightOnCommand(kitchenLight); LightOffCommand* kitchenLightOff=new LightOffCommand(kitchenLight); remoteControl->setCommand(0, livingRoomLightOn, livingRoomLightOff); remoteControl->setCommand(1,kitchenLightOn, kitchenLightOff); remoteControl->onButtonWasPushed(0); remoteControl->offButtonWasPushed(0); remoteControl->onButtonWasPushed(1); remoteControl->offButtonWasPushed(1); /* 其余代码省略 */ return 0;}