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Jim’s uncle found ( )in a mobile phone factory.There ( )always a lot of ( )for him to do.A、a work / are / worksB、a job/ is/ workC、a work/ is/ jobD、work/ is / job

题目
Jim’s uncle found ( )in a mobile phone factory.There ( )always a lot of ( )for him to do.

A、a work / are / works

B、a job/ is/ work

C、a work/ is/ job

D、work/ is / job

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1.2．—What's your _______ number?—________347- 5186．A． phone ;He'sB． bike ;That'sC． phone ;It'sD． bike's ;It's

2.Review the definition of the phone_list view.CHEATE OR REPLACE ALGORITHM=MERGE DEFINER= ‘root‘@localhost‘ SQL SECURITY DEFINER VIEW ‘phone_list‘ AS SELECTe . id as id ‘e . first_name AS ‘first_name‘ ‘e . last_name AS ‘last_name‘ ‘coalesce ( ph1.phone_no, ‘ – ‘) AS ‘office_no‘ ‘coalesce (ph2 .phone_no, ‘ – ‘) AS ‘cell_no‘ FROM employees e LEFT JOIN employee_phone ph1 ON ph1.emp_id = e.id AND ph1.type = ‘office‘ LEFT JOIN employee_phone ph2 ON ph2 .emp_id = e.id AND ph2 .type = ‘mobile‘The tables employees and employee_phone are InnoDB tables;all columns are used in this view. The contents of the phone_list view are as follows: Mysql> select * from phone_list; 1 row in set (0.00 sec)Which method can you use to change the cell_no value to ‘555-8888‘ for John Doe?（）A.INSERT INTO employee_phone (emp_id, phone_no, type) VALUES (1, ‘555-8888‘,‘mobile‘)B.UPDATE phone_list SET cell_name ‘555-8888‘ WHERE first_name= ‘John‘ and last_name= ‘Doe‘C.DELETE FROM phone_list WHERE first_name= ‘John‘ and last_name= ‘Doe‘; INSERT INTO phone_list (first_name, last_name, office_no, cell_no) VALUES (‘John‘ , ‘Doe‘ , ‘x1234‘ , ‘555-8888)D.UPDATE employee_phone SET phone_no= ‘555-8888‘ where emp_id=1

3.下列是基于过程块的组合逻辑建模的代码，设计正确的是（）A.reg y; reg a,b,clear; ... always@* if(clear) y=1'b0; always@* y=a & b;#B.always@* if (clear) y=1'b0; else y=a&b;#C.always@(a) y=a & b;#D.reg [1:0] s; ... case(s) 2'b00:y=1'b1; 2'b10:y=1'b0; 2'b11:y=1'b1; endcase

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更多“Jim’s uncle found ( )in a mobile phone factory.There ( )always a lot of ( )for him to do. ”相关问题

  • 第1题：

    4、以下的描述中，必然是对Mealy型状态机的描述的是？

    A.always @(*) case (state) S0: begin out = 0; if (in) next_state = S1; else next_state = S2; end ……#B.always @(*) case (state) S0: begin if (in) next_state = S1; else next_state = S0; end ……#C.always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……#D.以上答案均不正确
    always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……

  • 第2题：

    通过 SQL，在表 Actor 中选择 FirstName 等于 Jim 而 LastName 等于 Carter 的所有记录的表述正确的是（）。

    A．SELECT * FROM Actor WHERE FirstName LIKE 'Jim' AND LastName LIKE 'Carter'

    B．SELECT FirstName='Jim', LastName='Carter' FROM Actor

    C．SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter'

    D．SELECT * FROM Actor WHERE FirstName='Jim' OR LastName='Carter'


    SELECT * FROM Actor WHERE FirstName='Jim' AND LastName='Carter'

  • 第3题：

    2、下列不是合法标识符的是（）

    A．_abc

    B．a_s1

    C．d$shut

    D．always


    9moon

  • 第4题：

    请看一下代码，《插入代码》处应填入的代码是（）Map map=new HashMap（); map.put（“tom”,123.6); map.put（“jim”,234.5); map.put（“terry”,45.3); 《插入代码》 其中《插入代码》处要实现的功能是把key为“jim”的value值在原有数字的基础上添加100。

    A．map.put(“jim”,map.get(“jim”)+100);

    B．map.set(“jim”,map.get(“jim”)+100);

    C．map.put(“jim”,234.5);

    D．map.set(“jim”,234.5);


    map.put(“jim”,map.get(“jim”)+100);

  • 第5题：

    下列Moore型状态机采用Verilog语言主控时序部分正确的是：

    A．always@(posedge clk or negedge reset) begin if(!reset) current_state＜=s0; else current_state＜=next_state; end

    B．always@(posedge clk ) begin if(!reset) current_state＜=s0; else current_state＜=next_state; end

    C．always@(posedge clk t) if(reset) current_state＜=s0; else current_state＜=next_state;

    D．always@(posedge clk or negedge reset) if(reset) current_state＜=s0; else current_state＜=next_state;


    always@(posedge clk or negedge reset) begin if(!reset) current_state＜=s0; else current_state＜=next_state; end

  • 第6题：

    以下的描述中，必然是对Mealy型状态机的描述的是？

    A.always @(*) case (state) S0: begin out = 0; if (in) next_state = S1; else next_state = S2; end ……#B.always @(*) case (state) S0: begin if (in) next_state = S1; else next_state = S0; end ……#C.always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……#D.以上答案均不正确
    always @(*) case (state) S0: begin if (in) begin next_state = S1; out=1 end else next_state = S0; end ……

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