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A frustrated and angry customer calls in with a system that does not work. Which of the following is the FIRST course of action for a technician to take?()A. Transfer the customer to another technician, who can allocate more time to the issue.B. Maintain
题目
A. Transfer the customer to another technician, who can allocate more time to the issue.
B. Maintain a positive attitude and offer them the cheapest solution possible to satisfy them.
C. Listen to what the customer has to say and calmly recommend the best course of action.
D. Use technical language to demonstrate knowledge and expertise to the customer.
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第1题：
下列语句在控制台上的输出是().if(true)System.Console.WriteLine("First");System.Console.WriteLine("Second");
A. FirstSecond
B. First
C. Second
D. 无输出
正确答案：A
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第2题：
4．—_________ Mike________ his homework in the evening?
—No，he doesn't．
A． Do；does
B． Does；do
C． Do；do
D． Does；does
正确答案：B
4.B【解析】考查实义动词的疑问式为“Does+主语+do，故选B。 -
第3题：
Action API完成返回数据集中的元素个数的操作命令是（）。
A．first()
B．reduce(func)
C．count()
D．take(n)
count() -
第4题：
阅读以下说明和 Java程序，填补代码中的空缺，将解答填入答题纸的对应栏内。 【说明】 以下Java代码实现一个简单客户关系管理系统（CRM）中通过工厂（CustomerFactory ）对象来创建客户（Customer）对象的功能。客户分为创建成功的客户（RealCustomer）和空客户 （NullCustomer）。空客户对象是当不满足特定条件时创建或获取的对象。类间关系如图 5-1 所示。
图5-1 类图【Java代码】 Abstract class Customer﹛ Protected String name; （ 1 ）boolean isNil(); （ 2 ）String getName(); ﹜ Class RealCustomer （ 3 ）Customer{ Public RealCustomer(String name){ this.name=name; } Public String getName(){ return name ; } Public boolean is Nil() { return false; } ﹜ Class NullCustomer（ 4 ）Customer﹛ Public String getName()﹛ return "Not Available in Customer Database"; ﹜ Public boolean isNil() ﹛ return true; ﹜ ﹜ class Customerfactory { public String[] names = {"Rob"，"Joe"，"Julie"}; public Customer getCustomer(String name) { for (int i = 0; i < names.length;i++) { if (names[i].（ 5 ）)﹛ return new RealCustomer(name); ﹜ ﹜ return （ 6 ）; ﹜ ﹜ Public class CrM﹛ Public viod get Customer()﹛ Customerfactory（ 7 ）; Customer customer1-cf.getCustomer("Rob"); Customer customer2=cf.getCustomer("Bob"); Customer customer3= cf.getCustomer("Julie"); Customer customer4= cf.getCustomer("Laura"); System.out.println("customers”) System.out.println(customer1.getName()); System.out.println(customer2getName()); System.out.println(customer3.getName()); System.out.println(customer4.getName()); ﹜ Public static viod main (String[]arge)﹛ CRM crm =new CRM(); Crm.getCustomer(); ﹜ ﹜ /*程序输出为： Customers rob Not Available in Customer Database Julie Not Available in Customer Database */
正确答案：1）public abstract
2) public abstract
3)extends
4)extends
5)equals(name)
6)new Null Customer()
7) cf=New CustomerFactory();
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第5题：
Which of the following may illustrate the difference between "competence" and__________ "performance"?A．What a person "knows" and what he/she "does".
B．What a person "can do" and what he/she "does".
C．What a person "does" and what he/she "knows".
D．What a person "does" and what he/she "can do".答案：A解析：考查语言学知识。competence“语言能力”，指语言使用者对于语言规则系统的潜在意识；performance“语言运用”，指在具体场景中语言的实际运用，二者对应的分别为“knows”和“does”。故选A。 -
第6题：
Action API完成返回数据集中的前n个元素的操作命令是（）。
A．first()
B．reduce(func)
C．count()
D．take(n)
take(n)